9951 = 1 + 2 + 3 + 45 × (6 + 7) × (8 + 9)
9951 = 9876 + 5 × (4 × 3 + 2 + 1)
9951 = 0^7 + 1^9 + 2^8 + 3^3 + 4^6 + 5^5 + 6^2 + 7^4 + 8^1 + 9^0
a(n) = (n^3 + 2*n)/3, n = 31
9951 cannot be written as a sum of 3 squares. (Integers that are not a sum of three squares)
Sphenic number: Product of 3 distinct Primes, (List)
Factors: 1, 3, 31, 93, 107, 321, 3317, 9951
Nine thousand, nine hundred fifty-one
Representations, Binary to Hexadecimal:
10011011011111_2
111122120_3
2123133_4
304301_5
114023_6
41004_7
23337_8
14576_9
7527_11
5913_12
46b6_13
38ab_14
2e36_15
26df_16
<--- --->
Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
