96 = 1 × 2 + 3 + 4 × 5 + 6 + 7 × 8 + 9
96 = 9 + 8 × 7 + 6 + 5 × 4 + 3 + 2 × 1
96 = 0^0 + 1^8 + 2^7 − 3^9 + 4^5 + 5^6 + 6^1 + 7^4 + 8^3 + 9^2
a(n) = 6*n^2.
96 = (11 + 1) × (1 + 1)(1+1+1)
= 2 × 2 × (22 + 2)
= 3 × 33 − 3
= 4 × (4 × 4 + 4 + 4)
= 5 × (5 × 5 − 5) − 5 + 5/5
= 66 + 6 × 6 − 6
= 7 × (7 + 7) − (7 + 7)/7
= 88 + 8
= 99 − (9 + 9 + 9)/9
Number that is the sum of 3 positive 5th powers.
Numbers of edges of regular polygon constructible with unmarked straightedge and compass.
Numbers k such that (35*10^k - 11)/3 is prime
Factors: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96
Representations, Binary to Hexadecimal:
1100000_2
10120_3
1200_4
341_5
240_6
165_7
140_8
116_9
88_11
80_12
75_13
6c_14
66_15
60_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
