912 = 1 + 23 × 4 + 5 × 6 + 789
912 = 9 + 876 + 5 × 4 + 3 × 2 + 1
912 = 0^6 + 1^9 + 2^7 − 3^8 + 4^3 + 5^5 + 6^0 + 7^2 + 8^4 + 9^1
912 = (1 + 1)(11−1) − 111 − 1
912 = 2 × 2 × 222 + 22 + 2
912 = 3 × (3 × 3 × 33 + 3 + 3) + 3
912 = 4 × (44 − 4 × (4 + 4) + 4)
912 = 5 × 55 + (55 + 55 + 5)/5
912 = 6×((6+6)×(6+6)+6)+6+6
912 = (77 + 7) × (77 − 7/7)/7
912 = 888 + 8 + 8 + 8
912 = 9 × 99 + 9 + (99 + 9)/9
Sum of four consecutive primes.
Number k such that sigma(x) = k has exactly 7 solutions.
Factors: 1, 2, 3, 4, 6, 8, 12, 16, 19, 24, 38, 48, 57, 76, 114, 152, 228, 304, 456, 912
Representations, Binary to Hexadecimal:
1110010000_2
1020210_3
32100_4
12122_5
4120_6
2442_7
1620_8
1223_9
75a_11
640_12
552_13
492_14
40c_15
390_16
<--- --->
Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
