88

88 = 2 × 2 × 2 × 11

88 = 12 + 3 × 4 + 5 + 6 × 7 + 8 + 9

88 = 9 + 8 + 7 × 6 + 5 + 4 × 3 × 2 × 1

88 = 0^1 − 1^8 + 2^7 − 3^9 + 4^5 + 5^6 + 6^0 + 7^4 + 8^3 + 9^2

88 = 11 × (1 + 1)^(1+1+1)
= 2 × 2 × 22
= 3 × 33 − 33/3
= 44 + 44
= 5 × 5 + (5⁵/5 + 5)/(5 + 5)
= 66 + (66 + 66)/6
= 77 + 77/7
= 88
= 99 − 99/9

Strobogrammatic number: the same upside down.

Numbers k such that k^4 + 1 is prime.

Minimal number of people to give a 50% probability of having at least 3 coincident birthdays in one year.

Sum of four consecutive primes

Factors: 1, 2, 4, 8, 11, 22, 44, 88

Representations, Binary to Hexadecimal:

1011000_2
10021_3
1120_4
323_5
224_6
154_7
130_8
107_9
80_11
74_12
6a_13
64_14
5d_15
58_16

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