5463 = (1 + 23) × 4 × 56 + 78 + 9
5463 = 9 + 8 + 7 + 6 + 5432 + 1
5463 = 0^8 − 1^9 + 2^4 − 3^7 + 4^6 + 5^5 + 6^1 + 7^3 + 8^2 + 9^0
Number k such that k^4 can be written as a sum of four positive 4th powers with no common factor.
Sum of three consecutive pentagonal numbers.
5463 cannot be written as a sum of 3 squares. (Integers that are not a sum of three squares)
Factors: 1, 3, 9, 607, 1821, 5463
five thousand, four hundred sixty-three
Representations, Binary to Hexadecimal:
1010101010111_2
21111100_3
1111113_4
133323_5
41143_6
21633_7
12527_8
7440_9
4117_11
31b3_12
2643_13
1dc3_14
1943_15
1557_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
