52 = 12 − 3 − 45 + 6 − 7 + 89
52 = 98 − 76 + 54 − 3 − 21
52 = −0^0 + 1^8 + 2^7 − 3^9 + 4^5 + 5^6 + 6^2 + 7^4 + 8^3 + 9^1
52 = 4^2 + 6^2
52^2 = 20^2 + 48^2
52 = 1^2 + 1^2 + 1^2 + 7^2 = 1^2 + 1^2 + 5^2 + 5^2 = 2^2 + 4^2 + 4^2 + 4^2 = 3^2 + 3^2 + 3^2 + 5^2
52 = (1 + 1) × (1 + 1) × (11 + 1 + 1)
= 2 × (22 + 2 + 2)
= 33 + 33 − 3 + 3/3
= 4 + 4 + 44
= 55 − 5 + (5 + 5)/5
= ((6 + 6)/6)6 − 6 − 6
= 7 × 7 + (7 + 7 + 7)/7
= 8 + 88 × 8/(8 + 8)
= 9 × 9 − 9 − 9 − 99/9
Numbers k such that (8*10^k + 49)/3 is prime.
The ring of integers of the field Q(sqrt(-52)) has class number 2.
a(n) = n^3 - 3*n , n = 4
Fifty-two.
Representations, Binary to Hexadecimal:
110100_2
1221_3
310_4
202_5
124_6
103_7
64_8
57_9
48_11
44_12
40_13
3a_14
37_15
34_16
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