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5163 = 3 × 1721

5163 = 123 + (45 + 6 + 7) × 89

5163 = 9 × (87 + 6) + 5 + 4321

5163 = 0^5 + 1^7 + 2^9 − 3^8 + 4^6 + 5^1 + 6^2 + 7^0 + 8^3 + 9^4

Number k such that k^10 == 1 (mod 11^3).

Semiprime (Product of 2 Primes)

Factors: 1, 3, 1721, 5163

Ffive thousand, one hundred sixty-three

Representations, Binary to Hexadecimal:

1010000101011_2
21002020_3
1100223_4
131123_5
35523_6
21024_7
12053_8
7066_9
3974_11
2ba3_12
2472_13
1c4b_14
17e3_15
142b_16

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