497 = 12 × 34 + 5 + 67 + 8 + 9
497 = 9 + 8 + 7 × 65 + 4 × 3 × 2 + 1
497 = 0^4 + 1^6 + 2^8 − 3^9 + 4^7 + 5^5 + 6^1 + 7^3 + 8^2 + 9^0
Pentanacci numbers: a(n) = a(n-1) + a(n-2) + a(n-3) + a(n-4) + a(n-5) with a(0) = a(1) = a(2) = a(3) = a(4) = 1. n = 12
Number k such that (k! + 3)/3 is prime
Semiprime (Product of 2 Primes)
Factors: 1, 7, 71, 497
Representations, Binary to Hexadecimal:
111110001_2
200102_3
13301_4
3442_5
2145_6
1310_7
761_8
612_9
412_11
355_12
2c3_13
277_14
232_15
1f1_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
