4802 = 1 × 23 + 45 + 6 × 789
4802 = (9 + 8 + 76 + 5) × (4 + 3)2 × 1
4802 = 0^0 + 1^7 + 2^8 − 3^9 + 4^4 + 5^6 + 6^5 + 7^2 + 8^3 + 9^1
4802 = 49^2 + 49^2
Sum of three consecutive squares: a(n) = n^2 + (n + 1)^2 + (n + 2)^2. n = 39
Factors: 1, 2, 7, 14, 49, 98, 343, 686, 2401, 4802
Four thousand, eight hundred two
1001011000010_2
20120212_3
1023002_4
123202_5
34122_6
20000_7
11302_8
6525_9
3676_11
2942_12
2255_13
1a70_14
1652_15
12c2_16
<--- --->
Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
