4112 = 1 + 2 + 3 × 4 × 5 × 67 + 89
4112 = 9 + 8 + 7 × 65 × (4 + 3 + 2) × 1
4112 = 0^6 + 1^8 − 2^9 + 3^7 + 4^5 + 5^4 + 6^0 + 7^2 + 8^1 + 9^3
4112 = 4^2 + 64^2
4112 = 2^4 + 8^4
Positive number for which the sum of digits equals the product of digits.
A regular 4112-gon is constructible with straightedge and compass.
Factors: 1, 2, 4, 8, 16, 257, 514, 1028, 2056, 4112
Four thousand, one hundred twelve
Representations, Binary to Hexadecimal:
1000000010000_2
12122022_3
1000100_4
112422_5
31012_6
14663_7
10020_8
5568_9
30a9_11
2468_12
1b44_13
16da_14
1342_15
1010_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics

