3890 = 1 × 2 + 3 × (4 + 5) × 6 × (7 + 8 + 9)
3890 = 98 + 7 × 6 + 54 × 3 × 2 × 1
3890 = 0^5 − 1^9 + 2^8 − 3^7 + 4^6 + 5^1 + 6^4 + 7^3 + 8^0 + 9^2
3890 = 13^2 + 61^2 = 41^2 + 47^2
Sum of three consecutive squares: a(n) = n^2 + (n + 1)^2 + (n + 2)^2. n = 35
Sphenic number: Product of 3 distinct Primes, (List)
Factors: 1, 2, 5, 10, 389, 778, 1945, 3890
Three thousand, eight hundred ninety
Representations, Binary to Hexadecimal:
111100110010_2
12100002_3
330302_4
111030_5
30002_6
14225_7
7462_8
5302_9
2a17_11
2302_12
1a03_13
15bc_14
1245_15
f32_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics

