Goldbach partitions of 36 : (5, 31), (7, 29), (13, 23), (17, 19)
36 = 1234 + 5 + 6 + 7 + 8 + 9
36 = 98 − 7 − 6 − 5 − 43 − 2 + 1
36 = 0^6 + 1^7 + 2^9 − 3^8 + 4^0 + 5^5 + 6^2 + 7^4 + 8^3 + 9^1
36 = 1^3 + 2^3 + 3^3
36 = (1 + 1 + 1) × (11 + 1)
= (2 + 2 + 2)2
= 3 + 33
= 4 + 4 × (4 + 4)
= 5 × 5 + 55/5
= 6 × 6
= 7 × 7 − 7 − 7 + 7/7
= 88 × 8/(8 + 8) − 8
= 9 + 9 + 9 + 9
36, Sum of first n cubes
Sum of four consecutive primes
Number k such that (11*10^k + 19)/3 is prime
Number k such that (k! + 3)/3 is prime
Factors: 1, 2, 3, 4, 6, 9, 12, 18, 36
Representations, Binary to Hexadecimal:
100100_2
1100_3
210_4
121_5
100_6
51_7
44_8
40_9
33_11
30_12
2a_13
28_14
26_15
24_16
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