3470 = 12 + 34 + 5 × (678 + 9)
3470 = 9 + (8 + 7 + 65) × 43 + 21
3470 = 0^7 + 1^8 + 2^9 − 3^6 + 4^4 + 5^5 + 6^3 + 7^1 + 8^0 + 9^2
Sum of three consecutive squares: a(n) = n^2 + (n + 1)^2 + (n + 2)^2. n = 33
Sphenic number: Product of 3 distinct Primes, (List)
Factors: 1, 2, 5, 10, 347, 694, 1735, 3470
Three thousand, four hundred seventy
Representations, Binary to Hexadecimal:
110110001110_2
11202112_3
312032_4
102340_5
24022_6
13055_7
6616_8
4675_9
2675_11
2012_12
176c_13
139c_14
1065_15
d8e_16
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