3397 = (1 + 23 + 4 + 5 × 6) × (7 + 8 × 9)
3397 = (9 × 87 + 65) × 4 + 3 + 2 × 1
3397 = 0^5 + 1^7 + 2^1 + 3^9 − 4^8 + 5^3 + 6^6 + 7^4 + 8^2 + 9^0
Number k such that k^10 == 1 (mod 11^3).
Semiprime (Product of 2 Primes)
Factors: 1, 43, 79, 3397
Representations, Binary to Hexadecimal:
110101000101_2
11122211_3
311011_4
102042_5
23421_6
12622_7
6505_8
4584_9
2609_11
1b71_12
1714_13
1349_14
1017_15
d45_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
