3345 = (1 + 2 × 3 × 4 + 56 × 7) × 8 + 9
3345 = 98 + 7 + 6 × 54 × (32 + 1)
3345 = 0^6 + 1^8 + 2^9 − 3^7 + 4^1 + 5^5 + 6^4 + 7^0 + 8^3 + 9^2
Number n such that p=n^2+2 and p+2 are primes.
Factors: 1, 3, 5, 15, 223, 669, 1115, 3345
Three thousand, three hundred forty-five
Representations, Binary to Hexadecimal:
110100010001_2
11120220_3
310101_4
101340_5
23253_6
12516_7
6421_8
4526_9
2571_11
1b29_12
16a4_13
130d_14
ed0_15
d11_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics

