325 = 1 + 234 + 5 + 6 + 7 + 8 × 9
325 = 98 + 7 × 6 + 5 × (4 + 32 + 1)
325 = 0^8 − 1^9 + 2^6 − 3^7 + 4^5 + 5^4 + 6^1 + 7^0 + 8^2 + 9^3
325 = 1^2 + 18^2 = 6^2 + 17^2 = 10^2 + 15^2
325^2 = 36^2 + 323^2 = 204^2 + 253^2
325 divides 51^2 - 1.
Number of fractions in Farey series of order 32
\( 325=1^{2}+18^{2}=6^{2}+17^{2}=10^{2}+15^{2} \)
a(n) = n^2 + 1 (n=18)
Positive number whose product of digits is three times their sum.
Factors: 1, 5, 13, 25, 65, 325
Three hundred twenty-five
Representations, Binary to Hexadecimal:
101000101_2
110001_3
11011_4
2300_5
1301_6
643_7
505_8
401_9
276_11
231_12
1c0_13
193_14
16a_15
145_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics

