2925 = (1 × 23 + 4 × 56 + 78) × 9
2925 = 9 × 87 + (6 × 5 + 4) × 3 × 21
2925 = 0^7 + 1^9 + 2^8 + 3^6 + 4^5 + 5^4 + 6^3 + 7^0 + 8^2 + 9^1
2925 = 3^2 + 54^2 = 18^2 + 51^2 = 30^2 + 45^2
2925 = binomial(25 + 2, 3) is the 25th tetrahedral number.
a(n) = 1^2 + 3^2 + 5^2 + 7^2 + ... + (2*n-1)^2 = n*(4*n^2 - 1)/3, n = 13
Factors: 1, 3, 5, 9, 13, 15, 25, 39, 45, 65, 75, 117, 195, 225, 325, 585, 975, 2925
two thousand, nine hundred twenty-five
Representations, Binary to Hexadecimal:
101101101101_2
11000100_3
231231_4
43200_5
21313_6
11346_7
5555_8
4010_9
221a_11
1839_12
1440_13
10cd_14
d00_15
b6d_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics

