253

253 = 11 × 23

253 = 123 + 4 + 5 × 6 + 7 + 89

253 = 9 × (8 + 7 + 6) + 54 + 3² + 1

253 = 0^7 − 1^9 + 2^5 − 3^8 + 4^6 + 5^1 + 6^3 + 7^4 + 8^2 + 9^0

253 = 3^2 + 10^2 + 12^2

253 divides 45^2 - 1.

253 = 11 × (11 + 11 + 1)

253 = (22² + 22)/2

253 = 3 × 3 + (3⁽³⁺³⁾ + 3)/3

253 = 4⁴ − 4 + 4/4

253 = (5 − (5 + 5)/5)⁵ + 5 + 5

253 = 6 × (6 × 6 + 6) + 6/6

253 = 7 × (7 × 7 − 7 − 7) + 7 + 7/7

253 = (8 + 8) × (8 + 8) + 8 − 88/8

253 = 9 × (9 + 9 + 9) + 9 + 9/9

Pentanacci numbers: a(n) = a(n-1) + a(n-2) + a(n-3) + a(n-4) + a(n-5) with a(0) = a(1) = a(2) = a(3) = a(4) = 1. n = 11

Number of points of norm <= 9^2 in square lattice

Number k such that (7*10^k + 71)/3 is prime.

253 = binomial(22 + 1, 2) is the 22nd triangular number.

Positive number whose product of digits is three times their sum.

Centered 12-gonal number, or centered dodecagonal number: number of the form 6*k*(k-1) + 1.

Semiprime (Product of 2 Primes)

Factors: 1, 11, 23, 253

Two hundred fifty-three

11111101_2
100101_3
3331_4
2003_5
1101_6
511_7
375_8
311_9
210_11
191_12
166_13
141_14
11d_15
fd_16

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