249 = 12 + 3 × 45 + 6 + 7 + 89
249 = 98 + 7 + 6 × 5 × 4 + 3 + 21
249 = 0^6 + 1^8 + 2^9 − 3^7 + 4^5 + 5^4 + 6^3 + 7^2 + 8^1 + 9^0
249 divides 82^2 - 1.
249 = (.6+(6*(6+((6*6)-.6))))
Number k such that k^2 + 2 is prime
Number k such that the Woodall number kx2^k - 1 is prime
Number of ordered pairs of integers (x,y) with x^2+y^2 < 9^2
Factors: 1, 3, 83, 249
Two hundred forty-nine
Representations, Binary to Hexadecimal:
11111001_2
100020_3
3321_4
1444_5
1053_6
504_7
371_8
306_9
207_11
189_12
162_13
13b_14
119_15
f9_16
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Graduate Studies in Mathematics
