247

247 = 13 × 19

247 = 12 + 3⁴ + 5 × (6 + 7) + 89

247 = 9 + 87 + 65 + 43 × 2 × 1

247 = 0^6 − 1^8 + 2^9 − 3^7 + 4^5 + 5^4 + 6^3 + 7^2 + 8^1 + 9^0

247 divides 77^2 - 1.

247 = (66+((6+((6)!/.6...))/6))

\( \det\begin{pmatrix}
2 & 4 & 7\\
7 & 2 & 4\\
4 & 7 & 2
\end{pmatrix}
= 247 \)

Number k such that 9^k + 2 is prime.

Positive integers n that are equal to the determinant of the circulant matrix formed by the decimal digits of n

247 cannot be written as a sum of 3 squares. (Integers that are not a sum of three squares)

The ring of integers of the field Q(sqrt(-247)) has class number 6.

Semiprime (Product of 2 Primes)

Factors: 1, 13, 19, 247

Two hundred forty-seven

Representations, Binary to Hexadecimal:

11110111_2
100011_3
3313_4
1442_5
1051_6
502_7
367_8
304_9
205_11
187_12
160_13
139_14
117_15
f7_16

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