161 = 1 × 2 + 3 + 4 + 56 + 7 + 89
161 = 9 + 87 + 6 + 54 + 3 + 2 × 1
161 = 0^6 − 1^8 − 2^9 + 3^4 − 4^7 + 5^3 + 6^2 + 7^5 + 8^1 + 9^0
161 divides 22^2 - 1.
161 = (1 + 1) × (11 − 1 − 1)(1+1) − 1
161 = ((2(2+2) + 2)2 − 2)/2
161 = (3 + 3) × 33 − 3/3
161 = 4 × (44 − 4) + 4/4
161 = 5 + (55 − 5)/(5 × 5 − 5)
161 = (6 + 6) × (6 + 6) + 6 + 66/6
161 = 77 + 77 + 7
161 = 88 + 8 × 8 + 8 + 8/8
161 = 9 × (9 + 9) − 9/9
Palindrome k such that 3k + 1 is also a palindrome.
Number k such that k^10 == 1 (mod 11^3).
Number of intersections of diagonals in the interior of a regular 10-gon.
Factors: 1, 7, 23, 161
One hundred sixty-one
Representations, Binary to Hexadecimal:
10100001_2
12222_3
2201_4
1121_5
425_6
320_7
241_8
188_9
137_11
115_12
c5_13
b7_14
ab_15
a1_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
