2nd (n=1) Hexagonal prism number \((n+1)(3n^{2}+3n+1),\)
14 = 12 − 3 − 45 + 67 − 8 − 9
14 = 98 + 7 − 6 − 54 − 32 + 1
14 = 0^6 − 1^7 + 2^9 − 3^8 + 4^2 + 5^5 + 60^ + 7^4 + 8^3 + 9^1
14 = 11 + 1 + 1 + 1
= 2(2+2) − 2
= 3 + 33/3
= 4 + (44 − 4)/4 = 4 × 4 − 4 ÷√4 = 4 × (√4 + √4) − √4
= 5 + 5 + 5 − 5/5
= 6 + 6 + (6 + 6)/6
= 7 + 7
= 8 + 8 − (8 + 8)/8
= 9 + (99 − 9)/(9 + 9)
a(n) = n^4 - n, n = 2
Number k such that (2*k)!/k!-1 is prime.
Number k such that k! - 1 is Prime
Numbers k such that (35*10^k - 11)/3 is prime (1166666666666663)
Number of arrangements of 3 circles in the affine plane.
Keith number or Repfigit (Repetitive Fibonacci-like digit)
Number of Integer partitions of 14: 135
Factors: 1, 2, 7, 14
Representations, Binary to Hexadecimal:
1110_2
112_3
32_4
24_5
22_6
20_7
16_8
15_9
13_11
12_12
11_13
10_14
e_15
e_16
Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
