1300 = 123 + 4 × 5 + (6 + 7) × 89
1300 = 9 + 8 + 76 × 5 + 43 × 21
1300 = 0^0 + 1^6 − 2^8 − 3^9 + 4^7 + 5^5 + 6^4 + 7^3 + 8^1 + 9^2
1300 = 2^2 + 36^2 = 12^2 + 34^2 = 20^2 + 30^2
1300 divides 51^2 - 1.
Number k such that (16*10^k - 31)/3 is prime.
Number that is the sum of 4 positive 5th powers. 1300 = 1^5 + 2^5 + 3^5 + 4^5
Factors: 1, 2, 4, 5, 10, 13, 20, 25, 26, 50, 52, 65, 100, 130, 260, 325, 650, 1300
One thousand, three hundred
Representations, Binary to Hexadecimal:
10100010100_2
1210011_3
110110_4
20200_5
10004_6
3535_7
2424_8
1704_9
a82_11
904_12
790_13
68c_14
5ba_15
514_16
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Undergraduate Texts in Mathematics
Graduate Studies in Mathematics
