125

125 = 5 × 5 × 5

125 = 1 × 2 + 34 + 5 + 67 + 8 + 9

125 = 98 + 7 + 6 + 5 + 4 + 3 + 2 × 1

125 = 0^8 − 1^9 + 2^6 − 3^7 + 4^5 + 5^4 + 6^1 + 7^0 + 8^3 + 9^2

125 = 5^3

125 = 2^2 + 11^2 = 5^2 + 10^2

125^2 = 44^2 + 117^2

125 divides 57^4 - 1.

125 = 11⁽¹⁺¹⁾ + 1 + 1 + 1 + 1

125 = (22/2)² + 2 + 2

125 = (3 + 3 − 3/3)³

125 = 44 + (4 − 4/4)⁴

125 = 5 × 5 × 5

125 = 66 + 66 − 6 − 6/6

125 = 7 + 7 + 777/7

125 = 8 × (8 + 8) + 8 − 88/8

125 = 99 + 9 + 9 + 9 − 9/9

125 = 10² + 5² =11² + 2²= 5³

Cube: a(n) = n^3, n = 5

Canada perfect number: n such that the sum of digits^2 of n equals the sum of d|n, 1<d<n.

Factors: 1, 5, 25, 125

One hundred twenty-five

Representations, Binary to Hexadecimal:

1111101_2
11122_3
1331_4
1000_5
325_6
236_7
175_8
148_9
104_11
a5_12
98_13
8d_14
85_15
7d_16

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